10(5/2+x)=20

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Solution for 10(5/2+x)=20 equation: 



10(5/2+x)=20

We move all terms to the left:

10(5/2+x)-(20)=0



Domain of the equation: 2+x)!=0

We move all terms containing x to the left, all other terms to the right

x)!=-2

x!=-2/1

x!=-2

x∈R



We add all the numbers together, and all the variables

10(+x+5/2)-20=0

We multiply parentheses

10x-20+5/2*10=0

We multiply all the terms by the denominator


10x*2*10+5-20*2*10=0

We add all the numbers together, and all the variables

10x*2*10-395=0

Wy multiply elements

200x*1-395=0

Wy multiply elements

200x-395=0

We move all terms containing x to the left, all other terms to the right

200x=395

x=395/200

x=1+39/40

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