10(4x-7)=15(6x+2)

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Solution for 10(4x-7)=15(6x+2) equation: 



10(4x-7)=15(6x+2)

We move all terms to the left:

10(4x-7)-(15(6x+2))=0

We multiply parentheses

40x-(15(6x+2))-70=0



We calculate terms in parentheses: -(15(6x+2)), so:

15(6x+2)

We multiply parentheses

90x+30

Back to the equation:

-(90x+30)



We get rid of parentheses

40x-90x-30-70=0

We add all the numbers together, and all the variables

-50x-100=0

We move all terms containing x to the left, all other terms to the right

-50x=100

x=100/-50

x=-2

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