10(4x-6)-30x+40=2-1/4(4x-20)

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Solution for 10(4x-6)-30x+40=2-1/4(4x-20) equation: 



10(4x-6)-30x+40=2-1/4(4x-20)

We move all terms to the left:

10(4x-6)-30x+40-(2-1/4(4x-20))=0



Domain of the equation: 4(4x-20))!=0

x∈R



We add all the numbers together, and all the variables

-30x+10(4x-6)-(2-1/4(4x-20))+40=0

We multiply parentheses

-30x+40x-(2-1/4(4x-20))-60+40=0

We multiply all the terms by the denominator


-30x*4(4x-20))+40x*4(4x-20))-(2-1-60*4(4x-20))+40*4(4x-20))=0

Wy multiply elements

-480x^3(4-20))-(2-60*4(4x-20))+40*4(4x-1-20))=0

We do not support expression: x^3(4

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