10(4x-5)=-130

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Solution for 10(4x-5)=-130 equation: 



10(4x-5)=-130

We move all terms to the left:

10(4x-5)-(-130)=0

We add all the numbers together, and all the variables

10(4x-5)+130=0

We multiply parentheses

40x-50+130=0

We add all the numbers together, and all the variables

40x+80=0

We move all terms containing x to the left, all other terms to the right

40x=-80

x=-80/40

x=-2

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