10(4x+3)-8x=4(12+8x)-18

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Solution for 10(4x+3)-8x=4(12+8x)-18 equation: 



10(4x+3)-8x=4(12+8x)-18

We move all terms to the left:

10(4x+3)-8x-(4(12+8x)-18)=0

We add all the numbers together, and all the variables

10(4x+3)-8x-(4(8x+12)-18)=0

We add all the numbers together, and all the variables

-8x+10(4x+3)-(4(8x+12)-18)=0

We multiply parentheses

-8x+40x-(4(8x+12)-18)+30=0



We calculate terms in parentheses: -(4(8x+12)-18), so:

4(8x+12)-18

We multiply parentheses

32x+48-18

We add all the numbers together, and all the variables

32x+30

Back to the equation:

-(32x+30)



We add all the numbers together, and all the variables

32x-(32x+30)+30=0

We get rid of parentheses

32x-32x-30+30=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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