10(3y-4)=30-5y

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Solution for 10(3y-4)=30-5y equation: 



10(3y-4)=30-5y

We move all terms to the left:

10(3y-4)-(30-5y)=0

We add all the numbers together, and all the variables

10(3y-4)-(-5y+30)=0

We multiply parentheses

30y-(-5y+30)-40=0

We get rid of parentheses

30y+5y-30-40=0

We add all the numbers together, and all the variables

35y-70=0

We move all terms containing y to the left, all other terms to the right

35y=70

y=70/35

y=2

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