10(3x-4)=5(6-x)=19

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Solution for 10(3x-4)=5(6-x)=19 equation: 



10(3x-4)=5(6-x)=19

We move all terms to the left:

10(3x-4)-(5(6-x))=0

We add all the numbers together, and all the variables

10(3x-4)-(5(-1x+6))=0

We multiply parentheses

30x-(5(-1x+6))-40=0



We calculate terms in parentheses: -(5(-1x+6)), so:

5(-1x+6)

We multiply parentheses

-5x+30

Back to the equation:

-(-5x+30)



We get rid of parentheses

30x+5x-30-40=0

We add all the numbers together, and all the variables

35x-70=0

We move all terms containing x to the left, all other terms to the right

35x=70

x=70/35

x=2

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