10(3x-2)=109-10x

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Solution for 10(3x-2)=109-10x equation: 



10(3x-2)=109-10x

We move all terms to the left:

10(3x-2)-(109-10x)=0

We add all the numbers together, and all the variables

10(3x-2)-(-10x+109)=0

We multiply parentheses

30x-(-10x+109)-20=0

We get rid of parentheses

30x+10x-109-20=0

We add all the numbers together, and all the variables

40x-129=0

We move all terms containing x to the left, all other terms to the right

40x=129

x=129/40

x=3+9/40

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