10(3x-1)=8(3x+1)+30

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Solution for 10(3x-1)=8(3x+1)+30 equation: 



10(3x-1)=8(3x+1)+30

We move all terms to the left:

10(3x-1)-(8(3x+1)+30)=0

We multiply parentheses

30x-(8(3x+1)+30)-10=0



We calculate terms in parentheses: -(8(3x+1)+30), so:

8(3x+1)+30

We multiply parentheses

24x+8+30

We add all the numbers together, and all the variables

24x+38

Back to the equation:

-(24x+38)



We get rid of parentheses

30x-24x-38-10=0

We add all the numbers together, and all the variables

6x-48=0

We move all terms containing x to the left, all other terms to the right

6x=48

x=48/6

x=8

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