10(3x-1)=8(3x+1)+18

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Solution for 10(3x-1)=8(3x+1)+18 equation: 



10(3x-1)=8(3x+1)+18

We move all terms to the left:

10(3x-1)-(8(3x+1)+18)=0

We multiply parentheses

30x-(8(3x+1)+18)-10=0



We calculate terms in parentheses: -(8(3x+1)+18), so:

8(3x+1)+18

We multiply parentheses

24x+8+18

We add all the numbers together, and all the variables

24x+26

Back to the equation:

-(24x+26)



We get rid of parentheses

30x-24x-26-10=0

We add all the numbers together, and all the variables

6x-36=0

We move all terms containing x to the left, all other terms to the right

6x=36

x=36/6

x=6

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