10(3x+8)-12=-4+2(x+4)

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Solution for 10(3x+8)-12=-4+2(x+4) equation: 



10(3x+8)-12=-4+2(x+4)

We move all terms to the left:

10(3x+8)-12-(-4+2(x+4))=0

We multiply parentheses

30x-(-4+2(x+4))+80-12=0



We calculate terms in parentheses: -(-4+2(x+4)), so:

-4+2(x+4)

determiningTheFunctionDomain
2(x+4)-4

We multiply parentheses

2x+8-4

We add all the numbers together, and all the variables

2x+4

Back to the equation:

-(2x+4)



We add all the numbers together, and all the variables

30x-(2x+4)+68=0

We get rid of parentheses

30x-2x-4+68=0

We add all the numbers together, and all the variables

28x+64=0

We move all terms containing x to the left, all other terms to the right

28x=-64

x=-64/28

x=-2+2/7

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