10(3x+5)-5(2x+0)=2(7x+19)

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Solution for 10(3x+5)-5(2x+0)=2(7x+19) equation:


10(3x+5)-5(2x)=2(7x+19)

We simplify the equation to the form, which is simple to understand
10(3x+5)-5(2x)=2(7x+19)

Reorder the terms in parentheses
+(+30x+50)-5*(2x)=2*(7x+19)

Remove unnecessary parentheses
+30x+50-5+*(+2x+)=+2+*(+7x+19+)

Reorder the terms in parentheses
+30x+50+(-10x-0)=2*(7x+19)

Remove unnecessary parentheses
+30x+50-10x-0=+2+*(+7x+19+)

Reorder the terms in parentheses
+30x+50-10x-0=+(+14x+38)

Remove unnecessary parentheses
+30x+50-10x-0=+14x+38

We move all terms containing x to the left and all other terms to the right.
+30x-10x-14x=+38-50

We simplify left and right side of the equation.
+6x=-12

We divide both sides of the equation by 6 to get x.
x=-2

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