10(3b-2)+6=27

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Solution for 10(3b-2)+6=27 equation: 



10(3b-2)+6=27

We move all terms to the left:

10(3b-2)+6-(27)=0

We add all the numbers together, and all the variables

10(3b-2)-21=0

We multiply parentheses

30b-20-21=0

We add all the numbers together, and all the variables

30b-41=0

We move all terms containing b to the left, all other terms to the right

30b=41

b=41/30

b=1+11/30

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