10(30-2x)(20+2x)-600=6000

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Solution for 10(30-2x)(20+2x)-600=6000 equation: 



10(30-2x)(20+2x)-600=6000

We move all terms to the left:

10(30-2x)(20+2x)-600-(6000)=0

We add all the numbers together, and all the variables

10(-2x+30)(2x+20)-600-6000=0

We add all the numbers together, and all the variables

10(-2x+30)(2x+20)-6600=0

We multiply parentheses ..

10(-4x^2-40x+60x+600)-6600=0

We multiply parentheses

-40x^2-400x+600x+6000-6600=0

We add all the numbers together, and all the variables

-40x^2+200x-600=0

a = -40; b = 200; c = -600;
Δ = b2-4ac
Δ = 2002-4·(-40)·(-600)
Δ = -56000
Delta is less than zero, so there is no solution for the equation

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