10(3+c)=40

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Solution for 10(3+c)=40 equation: 



10(3+c)=40

We move all terms to the left:

10(3+c)-(40)=0

We add all the numbers together, and all the variables

10(c+3)-40=0

We multiply parentheses

10c+30-40=0

We add all the numbers together, and all the variables

10c-10=0

We move all terms containing c to the left, all other terms to the right

10c=10

c=10/10

c=1

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