10(2x-58x)=57

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Solution for 10(2x-58x)=57 equation: 



10(2x-58x)=57

We move all terms to the left:

10(2x-58x)-(57)=0

We add all the numbers together, and all the variables

10(-56x)-57=0

We multiply parentheses

-560x-57=0

We move all terms containing x to the left, all other terms to the right

-560x=57

x=57/-560

x=-57/560

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