10(2x-1)=8(2x+11)+14

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Solution for 10(2x-1)=8(2x+11)+14 equation:



10(2x-1)=8(2x+11)+14
We move all terms to the left:
10(2x-1)-(8(2x+11)+14)=0
We multiply parentheses
20x-(8(2x+11)+14)-10=0
We calculate terms in parentheses: -(8(2x+11)+14), so:
8(2x+11)+14
We multiply parentheses
16x+88+14
We add all the numbers together, and all the variables
16x+102
Back to the equation:
-(16x+102)
We get rid of parentheses
20x-16x-102-10=0
We add all the numbers together, and all the variables
4x-112=0
We move all terms containing x to the left, all other terms to the right
4x=112
x=112/4
x=28

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