10(2x-1)=7(2x+1)+13

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Solution for 10(2x-1)=7(2x+1)+13 equation: 



10(2x-1)=7(2x+1)+13

We move all terms to the left:

10(2x-1)-(7(2x+1)+13)=0

We multiply parentheses

20x-(7(2x+1)+13)-10=0



We calculate terms in parentheses: -(7(2x+1)+13), so:

7(2x+1)+13

We multiply parentheses

14x+7+13

We add all the numbers together, and all the variables

14x+20

Back to the equation:

-(14x+20)



We get rid of parentheses

20x-14x-20-10=0

We add all the numbers together, and all the variables

6x-30=0

We move all terms containing x to the left, all other terms to the right

6x=30

x=30/6

x=5

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