10(2x-1)=5(4x2)

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Solution for 10(2x-1)=5(4x2) equation: 



10(2x-1)=5(4x^2)

We move all terms to the left:

10(2x-1)-(5(4x^2))=0

determiningTheFunctionDomain
10(2x-1)-54x^2=0

We add all the numbers together, and all the variables

-54x^2+10(2x-1)=0

We multiply parentheses

-54x^2+20x-10=0

a = -54; b = 20; c = -10;
Δ = b2-4ac
Δ = 202-4·(-54)·(-10)
Δ = -1760
Delta is less than zero, so there is no solution for the equation

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