10(2x+5)=20-2(5x+10)

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Solution for 10(2x+5)=20-2(5x+10) equation: 



10(2x+5)=20-2(5x+10)

We move all terms to the left:

10(2x+5)-(20-2(5x+10))=0

We multiply parentheses

20x-(20-2(5x+10))+50=0



We calculate terms in parentheses: -(20-2(5x+10)), so:

20-2(5x+10)

determiningTheFunctionDomain
-2(5x+10)+20

We multiply parentheses

-10x-20+20

We add all the numbers together, and all the variables

-10x

Back to the equation:

-(-10x)



We get rid of parentheses

20x+10x+50=0

We add all the numbers together, and all the variables

30x+50=0

We move all terms containing x to the left, all other terms to the right

30x=-50

x=-50/30

x=-1+2/3

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