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10(2x+4)=5(4+4x)
We move all terms to the left:
10(2x+4)-(5(4+4x))=0
We add all the numbers together, and all the variables
10(2x+4)-(5(4x+4))=0
We multiply parentheses
20x-(5(4x+4))+40=0
We calculate terms in parentheses: -(5(4x+4)), so:We get rid of parentheses
5(4x+4)
We multiply parentheses
20x+20
Back to the equation:
-(20x+20)
20x-20x-20+40=0
We add all the numbers together, and all the variables
20!=0
There is no solution for this equation
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