10(2x+3)-20=3-4(8-5x)

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Solution for 10(2x+3)-20=3-4(8-5x) equation: 


Simplifying
10(2x + 3) + -20 = 3 + -4(8 + -5x)

Reorder the terms:
10(3 + 2x) + -20 = 3 + -4(8 + -5x)
(3 * 10 + 2x * 10) + -20 = 3 + -4(8 + -5x)
(30 + 20x) + -20 = 3 + -4(8 + -5x)

Reorder the terms:
30 + -20 + 20x = 3 + -4(8 + -5x)

Combine like terms: 30 + -20 = 10
10 + 20x = 3 + -4(8 + -5x)
10 + 20x = 3 + (8 * -4 + -5x * -4)
10 + 20x = 3 + (-32 + 20x)

Combine like terms: 3 + -32 = -29
10 + 20x = -29 + 20x

Add '-20x' to each side of the equation.
10 + 20x + -20x = -29 + 20x + -20x

Combine like terms: 20x + -20x = 0
10 + 0 = -29 + 20x + -20x
10 = -29 + 20x + -20x

Combine like terms: 20x + -20x = 0
10 = -29 + 0
10 = -29

Solving
10 = -29

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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