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10(2x+1)=5(4x+3)
We move all terms to the left:
10(2x+1)-(5(4x+3))=0
We multiply parentheses
20x-(5(4x+3))+10=0
We calculate terms in parentheses: -(5(4x+3)), so:We get rid of parentheses
5(4x+3)
We multiply parentheses
20x+15
Back to the equation:
-(20x+15)
20x-20x-15+10=0
We add all the numbers together, and all the variables
-5!=0
There is no solution for this equation
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