10(2x)+5=x-2(x-2)

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Solution for 10(2x)+5=x-2(x-2) equation: 



10(2x)+5=x-2(x-2)

We move all terms to the left:

10(2x)+5-(x-2(x-2))=0



We calculate terms in parentheses: -(x-2(x-2)), so:

x-2(x-2)

We multiply parentheses

x-2x+4

We add all the numbers together, and all the variables

-1x+4

Back to the equation:

-(-1x+4)



We get rid of parentheses

102x+1x-4+5=0

We add all the numbers together, and all the variables

103x+1=0

We move all terms containing x to the left, all other terms to the right

103x=-1

x=-1/103

x=-1/103

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