10(2t+1)-13=t-(t+2)

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Solution for 10(2t+1)-13=t-(t+2) equation: 



10(2t+1)-13=t-(t+2)

We move all terms to the left:

10(2t+1)-13-(t-(t+2))=0

We multiply parentheses

20t-(t-(t+2))+10-13=0



We calculate terms in parentheses: -(t-(t+2)), so:

t-(t+2)

We get rid of parentheses

t-t-2

We add all the numbers together, and all the variables

-2

Back to the equation:

-(-2)



We add all the numbers together, and all the variables

20t-1=0

We move all terms containing t to the left, all other terms to the right

20t=1

t=1/20

t=1/20

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