10(2c-5)=36c-5

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Solution for 10(2c-5)=36c-5 equation: 



10(2c-5)=36c-5

We move all terms to the left:

10(2c-5)-(36c-5)=0

We multiply parentheses

20c-(36c-5)-50=0

We get rid of parentheses

20c-36c+5-50=0

We add all the numbers together, and all the variables

-16c-45=0

We move all terms containing c to the left, all other terms to the right

-16c=45

c=45/-16

c=-2+13/16

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