10(28+b)+15(5)=495

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Solution for 10(28+b)+15(5)=495 equation: 



10(28+b)+15(5)=495

We move all terms to the left:

10(28+b)+15(5)-(495)=0

We add all the numbers together, and all the variables

10(b+28)+155-495=0

We add all the numbers together, and all the variables

10(b+28)-340=0

We multiply parentheses

10b+280-340=0

We add all the numbers together, and all the variables

10b-60=0

We move all terms containing b to the left, all other terms to the right

10b=60

b=60/10

b=6

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