10(2/3)=r+12(1/6)*

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Solution for 10(2/3)=r+12(1/6)* equation:



10(2/3)=r+12(1/6)*
We move all terms to the left:
10(2/3)-(r+12(1/6)*)=0
We add all the numbers together, and all the variables
-(r+12(+1/6)*)+10(+2/3)=0
We multiply parentheses
-(r+12(+1/6)*)+2/3*10=0
We calculate fractions
(-(r+12(+1*3*10)/()+()/()=0
We calculate terms in parentheses: +(-(r+12(+1*3*10)/()+()/(), so:
-(r+12(+1*3*10)/()+()/(
We can not solve this equation

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