10(2-z)=4(2-9)

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Solution for 10(2-z)=4(2-9) equation: 



10(2-z)=4(2-9)

We move all terms to the left:

10(2-z)-(4(2-9))=0

We add all the numbers together, and all the variables

10(-1z+2)-(4(-7))=0

We add all the numbers together, and all the variables

10(-1z+2)+28=0

We multiply parentheses

-10z+20+28=0

We add all the numbers together, and all the variables

-10z+48=0

We move all terms containing z to the left, all other terms to the right

-10z=-48

z=-48/-10

z=4+4/5

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