10(2+3b)=-20

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Solution for 10(2+3b)=-20 equation: 



10(2+3b)=-20

We move all terms to the left:

10(2+3b)-(-20)=0

We add all the numbers together, and all the variables

10(3b+2)-(-20)=0

We add all the numbers together, and all the variables

10(3b+2)+20=0

We multiply parentheses

30b+20+20=0

We add all the numbers together, and all the variables

30b+40=0

We move all terms containing b to the left, all other terms to the right

30b=-40

b=-40/30

b=-1+1/3

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