10(18)=x(x+3)

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Solution for 10(18)=x(x+3) equation:



10(18)=x(x+3)
We move all terms to the left:
10(18)-(x(x+3))=0
We calculate terms in parentheses: -(x(x+3)), so:
x(x+3)
We multiply parentheses
x^2+3x
Back to the equation:
-(x^2+3x)
We get rid of parentheses
-x^2-3x+1018=0
We add all the numbers together, and all the variables
-1x^2-3x+1018=0
a = -1; b = -3; c = +1018;
Δ = b2-4ac
Δ = -32-4·(-1)·1018
Δ = 4081
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{4081}}{2*-1}=\frac{3-\sqrt{4081}}{-2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{4081}}{2*-1}=\frac{3+\sqrt{4081}}{-2} $

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