10(120+m)=4(150+m)

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Solution for 10(120+m)=4(150+m) equation: 



10(120+m)=4(150+m)

We move all terms to the left:

10(120+m)-(4(150+m))=0

We add all the numbers together, and all the variables

10(m+120)-(4(m+150))=0

We multiply parentheses

10m-(4(m+150))+1200=0



We calculate terms in parentheses: -(4(m+150)), so:

4(m+150)

We multiply parentheses

4m+600

Back to the equation:

-(4m+600)



We get rid of parentheses

10m-4m-600+1200=0

We add all the numbers together, and all the variables

6m+600=0

We move all terms containing m to the left, all other terms to the right

6m=-600

m=-600/6

m=-100

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