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10(1/5x+2)=-46
We move all terms to the left:
10(1/5x+2)-(-46)=0
Domain of the equation: 5x+2)!=0We add all the numbers together, and all the variables
x∈R
10(1/5x+2)+46=0
We multiply parentheses
10x+20+46=0
We add all the numbers together, and all the variables
10x+66=0
We move all terms containing x to the left, all other terms to the right
10x=-66
x=-66/10
x=-6+3/5
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