10(1/2+2)-5=3(x-6)+1

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Solution for 10(1/2+2)-5=3(x-6)+1 equation: 



10(1/2+2)-5=3(x-6)+1

We move all terms to the left:

10(1/2+2)-5-(3(x-6)+1)=0

We multiply parentheses

-(3(x-6)+1)-5+20+1/2*10=0

We multiply all the terms by the denominator


-((3(x-6)+1))*2*10+1-5*2*10+20*2*10=0

We add all the numbers together, and all the variables

-((3(x-6)+1))*2*10+301=0

We move all terms containing x to the left, all other terms to the right

-((3(x-6)+1))*2*10=-301

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