10(-4x+3)=8+(2x-3)

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Solution for 10(-4x+3)=8+(2x-3) equation: 



10(-4x+3)=8+(2x-3)

We move all terms to the left:

10(-4x+3)-(8+(2x-3))=0

We multiply parentheses

-40x-(8+(2x-3))+30=0



We calculate terms in parentheses: -(8+(2x-3)), so:

8+(2x-3)

determiningTheFunctionDomain
(2x-3)+8

We get rid of parentheses

2x-3+8

We add all the numbers together, and all the variables

2x+5

Back to the equation:

-(2x+5)



We get rid of parentheses

-40x-2x-5+30=0

We add all the numbers together, and all the variables

-42x+25=0

We move all terms containing x to the left, all other terms to the right

-42x=-25

x=-25/-42

x=25/42

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