10(-3-2y)+10-2(6y-13)=0

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Solution for 10(-3-2y)+10-2(6y-13)=0 equation: 



10(-3-2y)+10-2(6y-13)=0

We add all the numbers together, and all the variables

10(-2y-3)-2(6y-13)+10=0

We multiply parentheses

-20y-12y-30+26+10=0

We add all the numbers together, and all the variables

-32y+6=0

We move all terms containing y to the left, all other terms to the right

-32y=-6

y=-6/-32

y=3/16

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