10(-3-2t)+10-2(6t-13)=

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Solution for 10(-3-2t)+10-2(6t-13)= equation:



10(-3-2t)+10-2(6t-13)=
We move all terms to the left:
10(-3-2t)+10-2(6t-13)-()=0
We add all the numbers together, and all the variables
10(-2t-3)-2(6t-13)+10-()=0
We add all the numbers together, and all the variables
10(-2t-3)-2(6t-13)=0
We multiply parentheses
-20t-12t-30+26=0
We add all the numbers together, and all the variables
-32t-4=0
We move all terms containing t to the left, all other terms to the right
-32t=4
t=4/-32
t=-1/8

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