1/z+1/(x+4)=0

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Solution for 1/z+1/(x+4)=0 equation: 


D( x )

x+4 = 0

x+4 = 0

x+4 = 0

x+4 = 0 // - 4

x = -4

x in (-oo:-4) U (-4:+oo)

1/(x+4)+1/z = 0

(1*z)/(z*(x+4))+(1*(x+4))/(z*(x+4)) = 0

1*(x+4)+1*z = 0

x+z+4 = 0

(x+z+4)/(z*(x+4)) = 0

(x+z+4)/(z*(x+4)) = 0 // * z*(x+4)

x+z+4 = 0

x+z+4 = 0 // - z+4

x = -(z+4)

x = -(z+4)

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