1/y-1=1-y/2

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Solution for 1/y-1=1-y/2 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

1/y-1 = 1-(y/2) // - 1-(y/2)

y/2+1/y-1-1 = 0

1/2*y^1+1*y^-1-2*y^0 = 0

(1/2*y^2-2*y^1+1*y^0)/(y^1) = 0 // * y^2

y^1*(1/2*y^2-2*y^1+1*y^0) = 0

y^1

(1/2)*y^2-2*y+1 = 0

(1/2)*y^2-2*y+1 = 0

DELTA = (-2)^2-(1*4*(1/2))

DELTA = 2

DELTA > 0

y = (2^(1/2)+2)/(2*(1/2)) or y = (2-2^(1/2))/(2*(1/2))

y = 2^(1/2)+2 or y = 2-2^(1/2)

y in { 2-2^(1/2), 2^(1/2)+2} 

y in { 2-2^(1/2), 2^(1/2)+2 }

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