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1/x=3/3x-5
We move all terms to the left:
1/x-(3/3x-5)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 3x-5)!=0We get rid of parentheses
x∈R
1/x-3/3x+5=0
We calculate fractions
3x/3x^2+(-3x)/3x^2+5=0
We multiply all the terms by the denominator
3x+(-3x)+5*3x^2=0
Wy multiply elements
15x^2+3x+(-3x)=0
We get rid of parentheses
15x^2+3x-3x=0
We add all the numbers together, and all the variables
15x^2=0
a = 15; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·15·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{30}=0$
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