1/x=1/3-2/(3x)

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Solution for 1/x=1/3-2/(3x) equation: 


D( x )

3*x = 0

x = 0

3*x = 0

3*x = 0

3*x = 0 // : 3

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x = 1/3-(2/(3*x)) // - 1/3-(2/(3*x))

1/x+2/(3*x)-(1/3) = 0

1/x+2/(3*x)-1/3 = 0

5/3*x^-1 = 1/3 // : 5/3

x^-1 = 1/5

-1 < 0

1/(x^1) = 1/5 // * x^1

1 = 1/5*x^1 // : 1/5

5 = x^1

x = 5

x = 5

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