1/x=1/3-2(3x)

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Solution for 1/x=1/3-2(3x) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x = 1/3-(2*3*x) // - 1/3-(2*3*x)

2*3*x+1/x-(1/3) = 0

2*3*x+1/x-1/3 = 0

6*x^1+1*x^-1-1/3*x^0 = 0

(6*x^2-1/3*x^1+1*x^0)/(x^1) = 0 // * x^2

x^1*(6*x^2-1/3*x^1+1*x^0) = 0

x^1

6*x^2+(-1/3)*x+1 = 0

6*x^2+(-1/3)*x+1 = 0

DELTA = (-1/3)^2-(1*4*6)

DELTA = -215/9

DELTA < 0

x in { } 

x belongs to the empty set

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