1/x=0.02x

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Solution for 1/x=0.02x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x = 0.02*x // - 0.02*x

1/x-(0.02*x) = 0

1/x-0.02*x = 0

x^-1-0.02*x = 0

x^-1*(1-0.02*x^2) = 0

-0.02*x^2 = -1 // : -0.02

x^2 = 50

x^2 = 50 // ^ 1/2

abs(x) = 5*2^(1/2)

x = 5*2^(1/2) or x = -(5*2^(1/2))

1/x = 0

1*x^-1 = 0 // : 1

x^-1 = 0

x należy do O

x in { 5*2^(1/2), -(5*2^(1/2)) }

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