1/x=(4/3x)+1

Solution for 1/x=(4/3x)+1 equation:

D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x = (4/3)*x+1 // - (4/3)*x+1

1/x-((4/3)*x)-1 = 0

(-4/3)*x+1/x-1 = 0

1*x^-1-4/3*x^1-1*x^0 = 0

(1*x^0-4/3*x^2-1*x^1)/(x^1) = 0 // * x^2

x^1*(1*x^0-4/3*x^2-1*x^1) = 0

x^1

(-4/3)*x^2-x+1 = 0

(-4/3)*x^2-x+1 = 0

DELTA = (-1)^2-(1*4*(-4/3))

DELTA = 19/3

DELTA > 0

x = ((19/3)^(1/2)+1)/(2*(-4/3)) or x = (1-(19/3)^(1/2))/(2*(-4/3))

x = -3/8*((19/3)^(1/2)+1) or x = -3/8*(1-(19/3)^(1/2))

x in { -3/8*((19/3)^(1/2)+1), -3/8*(1-(19/3)^(1/2))} 

x in { -3/8*((19/3)^(1/2)+1), -3/8*(1-(19/3)^(1/2)) }