1/x-3/(x+2)=3/(x+2)

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Solution for 1/x-3/(x+2)=3/(x+2) equation: 



1/x-3/(x+2)=3/(x+2)

We move all terms to the left:

1/x-3/(x+2)-(3/(x+2))=0



Domain of the equation: x!=0

x∈R





Domain of the equation: (x+2)!=0

We move all terms containing x to the left, all other terms to the right

x!=-2

x∈R





Domain of the equation: (x+2))!=0

x∈R



We calculate fractions


(1*(x+2)*(x+2)))/(x*(x+2)*(x+2)))+(-3x^2*()/(x*(x+2)*(x+2)))+(-(3x^2*())/(x*(x+2)*(x+2)))=0



We calculate terms in parentheses: +(1*(x+2)*(x+2)))/(x*(x+2)*(x+2)))+(-3x^2*()/(x*(x+2)*(x+2)))+(-(3x^2*())/(x*(x+2)*(x+2))), so:

1*(x+2)*(x+2)))/(x*(x+2)*(x+2)))+(-3x^2*()/(x*(x+2)*(x+2)))+(-(3x^2*())/(x*(x+2)*(x+2))

determiningTheFunctionDomain
2)))+(-3x^2*()/(x*(x+1*(x+2)*(x+2)))/(x*(x+2)*(x+2)*(x+2)))+(-(3x^2*())/(x*(x+2)*(x+2))

We add all the numbers together, and all the variables

2)))+(-3x^2*()/(x*(x+1*(x+2)*(x+2)))/(x*(x+2)*(x+2)*(x+2)))+(-(3x^2*())/(x*(x+2)*(x

We multiply all the terms by the denominator


2)))+(-3x^2*()+1*(x+2)*(x+2)))+2*x*(x*(x+2*x*(x*(x+2)))+(-(3x^2*())+2*x*(x*(x

Back to the equation:

+(2)))+(-3x^2*()+1*(x+2)*(x+2)))+2*x*(x*(x+2*x*(x*(x+2)))+(-(3x^2*())+2*x*(x*(x)

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