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1/x-3-1/x+3=6/(x+3)(x-3)
We move all terms to the left:
1/x-3-1/x+3-(6/(x+3)(x-3))=0
Domain of the equation: x!=0
x∈R
Domain of the equation: (x+3)(x-3))!=0We add all the numbers together, and all the variables
x∈R
1/x-1/x-(6/(x+3)(x-3))=0
We use the square of the difference formula
x^2+1/x-1/x+9=0
We multiply all the terms by the denominator
x^2*x+9*x+1-1=0
We add all the numbers together, and all the variables
x^2*x+9x=0
Wy multiply elements
x^3+9x=0
We do not support expression: x^3
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