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1/x-3+2/x-2=8/x
We move all terms to the left:
1/x-3+2/x-2-(8/x)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/x+2/x-(+8/x)-3-2=0
We add all the numbers together, and all the variables
1/x+2/x-(+8/x)-5=0
We get rid of parentheses
1/x+2/x-8/x-5=0
We multiply all the terms by the denominator
-5*x+1+2-8=0
We add all the numbers together, and all the variables
-5x-5=0
We move all terms containing x to the left, all other terms to the right
-5x=5
x=5/-5
x=-1
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