1/x-2-3/x+6=8/x2+4x-12

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Solution for 1/x-2-3/x+6=8/x2+4x-12 equation: 



1/x-2-3/x+6=8/x2+4x-12

We move all terms to the left:

1/x-2-3/x+6-(8/x2+4x-12)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: x2+4x-12)!=0

x∈R



We add all the numbers together, and all the variables

1/x-3/x-(4x+8/x2-12)-2+6=0

We add all the numbers together, and all the variables

1/x-3/x-(4x+8/x2-12)+4=0

We get rid of parentheses

1/x-3/x-4x-8/x2+12+4=0

We calculate fractions

We do not support expression: x^3

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