1/x-2+x=8/2x-5

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Solution for 1/x-2+x=8/2x-5 equation:



1/x-2+x=8/2x-5
We move all terms to the left:
1/x-2+x-(8/2x-5)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x-5)!=0
x∈R
We add all the numbers together, and all the variables
x+1/x-(8/2x-5)-2=0
We get rid of parentheses
x+1/x-8/2x+5-2=0
We calculate fractions
x+2x/2x^2+(-8x)/2x^2+5-2=0
We add all the numbers together, and all the variables
x+2x/2x^2+(-8x)/2x^2+3=0
We multiply all the terms by the denominator
x*2x^2+2x+(-8x)+3*2x^2=0
We add all the numbers together, and all the variables
2x+x*2x^2+(-8x)+3*2x^2=0
Wy multiply elements
2x^3+6x^2+2x+(-8x)=0
We get rid of parentheses
2x^3+6x^2+2x-8x=0
We do not support expression: x^3

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