1/x-2+1/x=8/2x+5

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Solution for 1/x-2+1/x=8/2x+5 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x+1/x-2 = (8/2)*x+5 // - (8/2)*x+5

1/x-((8/2)*x)+1/x-5-2 = 0

1/x-4*x+1/x-5-2 = 0

2*x^-1-4*x^1-7*x^0 = 0

(2*x^0-4*x^2-7*x^1)/(x^1) = 0 // * x^2

x^1*(2*x^0-4*x^2-7*x^1) = 0

x^1

2-4*x^2-7*x = 0

2-4*x^2-7*x = 0

DELTA = (-7)^2-(-4*2*4)

DELTA = 81

DELTA > 0

x = (81^(1/2)+7)/(-4*2) or x = (7-81^(1/2))/(-4*2)

x = -2 or x = 1/4

x in { -2, 1/4} 

x in { -2, 1/4 }

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